Solve for x by simplifying both sides of the equation, then isolating the variable.
x = 5
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Step-by-step explanation:
Answer:
<h2>15 and 4</h2>
Step-by-step explanation:
Let the first integer be x and the second integer be y. If the first integer is 7 more than 2 times another, then x = 7+2y
The two integers will be y and 7+2y. If the product of both integers is 60, then;
y(7+2y) = 60
7y + 2y² = 60
2y² + 7y -60 = 0
2y²-8y+15y-60 = 0
2y(y-4)+15(y-4) = 0
(2y+15)(y-4) = 0
2y+15= 0 and y-4 = 0
2y = -15 and y = 4
y = -15/2 and 4
Taking the positive integer, y = 4
To get the other integer, we will substitute y = 4 into the equation x = 7+2y;
x = 7+2(4)
x = 7+8
x = 15
Hence the two integrs are 15 and 4
Answer:
sorry i dont know
Step-by-step explanation:
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- The value of the n is 8.
- There are 7 positive integers between 100 and 200 which are divisible by 14.
<u>Step-by-step explanation:</u>
The sum of first n odd positive integer is n^2. The nth odd number is 2n-1.
i.e. 1 + 3 + ........+ (2n-1) = n^2.
1 + 3 +..........+ (2n-1) = 64
n^2 = 64
n = 8.
The positive integers between 100 and 200 which are divisible by 14 are 112, 126, 140, 154, 168, 182, 196. It is obtained by the multiples of 14 between 100 and 200.
100 = 7 * 14 + 2
200 = 14 * 14 + 4. The answer is 14 - 7 = 7
The seven numbers are
14 * 8 = 112
14 * 9 = 126
14 * 10 = 140
14 * 11 = 154
14 * 12 = 168
14 * 13 = 182
14 * 14 = 196