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3 years ago

14 fl oz = how many cups

Mathematics

1 answer:

sertanlavr [38]3 years ago

8 0

1.75 us cups is equal to 14 fl oz

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Allen is on the football team this year but he has poor time management skills. His mother told him that he is off the team if h

luda_lava [24]

Answer:

See explanation

Step-by-step explanation:

We can see that the sequence is 90, 86,82,.......

The common difference is 86 - 90 = -4

82 - 86 = -4

Hence the sequence is arithmetic

The function is;

t(n) = 90 + (n - 1)(-4) = 90 + 4 - 4n

t(n) = 94 - 4n

Since it is AP, we have the sequence as;

90, 86, 82, 78, 74, 70, 66, 62......

He will no longer play football after the eighth quiz.

The total points earned is the sum of the first eight terms of the AP

Sn =n/2[2a + (n - 1) d]

Sn = 8/2[2(90) + (8 - 1) (-4)]

Sn = 608 points

5 0

3 years ago

According to the 2000 Census the population of Canton was 7,720. Holly Spring's population was 3,200. Canton's population increa

Kazeer [188]

Firstly, the rate of increase of Canton = 80/7720 = 0.010
The rate of increase of HP = 120/3200 = 0.0375
Apply the formula of compound interest==> A =A'(1+i)^n
The population will be equal when the following equality is satisfied

7720(1+0.01)^n = 3200(1+0.0375)^n

or

7720x1.01^n = 3200x1.0375^n

Divide both sides by 3200 ===>(193/80)x1.01^n=1.0375^n

8 0

3 years ago

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Predict whether the product will be greater than, less than or equal to the second factor. 1/5 x 3/4

charle [14.2K]

Answer:

Step-by-step explanation:

6 0

2 years ago

60 POINTS I NEED ANSWER FAST. WILL MARK BRAINLIEST.

Deffense [45]

Answer:

5.2

Step-by-step explanation:

4.3/5.6 = 4/AB

AB = 5.2

4 0

2 years ago

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(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)

laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if $K(t)\neq 0$

Example of a second order nonlinear ODE:

$Y=-3K(Y){2}$

(D) Example of a nonlinear fourth order ODE:

$K^4(x) - \beta f [x, k(x)] = 0$

4 0

3 years ago