It will be living two places to the edith hope this helps good luck
Given that f(x) = x/(x - 3) and g(x) = 1/x and the application of <em>function</em> operators, f ° g (x) = 1/(1 - 3 · x) and the domain of the <em>resulting</em> function is any <em>real</em> number except x = 1/3.
<h3>How to analyze a composed function</h3>
Let be f and g functions. Composition is a <em>binary function</em> operation where the <em>variable</em> of the <em>former</em> function (f) is substituted by the <em>latter</em> function (g). If we know that f(x) = x/(x - 3) and g(x) = 1/x, then the <em>composed</em> function is:



The domain of the function is the set of x-values such that f ° g (x) exists. In the case of <em>rational</em> functions of the form p(x)/q(x), the domain is the set of x-values such that q(x) ≠ 0. Thus, the domain of f ° g (x) is
.
To learn more on composed functions: brainly.com/question/12158468
#SPJ1
X + y = 1
add - y both sides
x + y + - y = 1 + - y
x = - y + 1
Answer: x = - y + 1
Graph: y = - x + 1
x + 7y = - 4
add - 7 both sides
x + 7y + - 7y = - 4 + -7y
x = - 7y - 4
Answer: x = - 7y - 4
Graph: y = 0.142857x - 0.571429
2x - 6y = 4
add 6y to both sides
2x - 6y + 6y = 4 + 6y
2x = 6y + 4
divide both sides by 2
2x/2 = 6y + 4/2
x = 3y + 2
Answer: x = 3y + 2
Graph: y = 0.333333x - 0.666667
5x + 15y = - 10
add - 15 to both sides
5x + 15y + - 15y = - 10 + - 15y
5x = - 15y - 10
divide both sides by 5
5x/5 = - 15y - 10/5
x = - 3y - 2
Answer: x = - 3y - 2
Graph: y = - 0.333333x - 0.666667
2x + 6y = 10
add - 6y to both sides
2x + 6y + - 6y = 10 + - 6y
2x = - 6y + 10
divide both sides by 2
2x/2 = - 6y + 10/2
x = - 3y + 5
Answer: x = -3y + 5
Graph: y = - 0.333333x + 1.666667
Hope that helps!!!
Answer:
Below.
Step-by-step explanation:
So let's do this Divide both sides.
equals to,
y+2>2
Cancel out equal terms.
y>0.
Answer:
If there are 2 quarters for every 3 nickels,
then there are
quarters.
If there are 2 dimes for every quarter,
then there are
dimes.
If the number of pennies and nickels together are equal to the number of dimes, then there are
pennies.