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MrRissso [65]
3 years ago
13

Which relation is a function?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0
Q2c i think that the right one 
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Layton has two hamsters.Each hamster drinks 3 centiliters.He fills a water bottle that holds 16 centiliters of water.How many ce
eduard

Answer:

10 centiliters

Step-by-step explanation:

Given data:

2 hamsters are available

1 hamster drinks 3 centiliters

16 centiliters are put

1 hamster drink 3 centiliters therefor 2 hamsters drinks (3 * 2) centiliters = 6 centiliters

<em>Assuming 1 hamster drinks 3 centiliters a day</em>

Remaining centiliters of water will be (16 - 6) = 10 centiliters.

4 0
3 years ago
Let f(x)=5x+2 find f(-6)
LuckyWell [14K]

Answer:

-28

Step-by-step explanation:

Plugging in -6 as x we get 5(-6) + 2, which simplifies to -30 + 2 or -28.

8 0
3 years ago
A 2-digit number is 12 times its tens digit. The sum of the digits is 12. What is the tens digit?
Goryan [66]
C) or 2 is the solution to your question c:
8 0
4 years ago
Read 2 more answers
Please help if you can. I will give Brainiest to best answer. This question is a Calculus/Trigonometry question. I ask that you
Ierofanga [76]

7 is incorrect. The answer should be -4. Here's how I'd derive it:

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

With \pi, we should expect \cos x. If \tan x=\dfrac8{15}, then

\sec x=-\sqrt{1+\tan^2x}=-\dfrac{17}{15}\implies\cos x=-\dfrac{15}{17}

Also,

\pi

so we should expect \tan\dfrac x2 and

\tan\dfrac x2=-\sqrt{\dfrac{1-\cos x}{1+\cos x}}=-4

You seem to be taking

\tan\dfrac x2=\dfrac{1+\cos x}{-\sin x}

but this is not an identity.

###

8 is incorrect. Just a silly mistake, you swapped the order of the terms in the numerator. It should be

\dfrac{\sqrt6-\sqrt2}4

###

9. Use the identity from (7). \dfrac{7\pi}{12} lies in the second quadrant, so

\tan\dfrac{7\pi}{12}=-\sqrt{\dfrac{1-\cos\frac{7\pi}6}{1+\cos\frac{7\pi}6}}=-\sqrt{7+4\sqrt3}=-2-\sqrt3

###

12.

\dfrac{\cot x-1}{1-\tan x}=\dfrac{\frac{\cos x}{\sin x}-1}{1-\frac{\sin x}{\cos x}}

=\dfrac{\cos x(\cos x-\sin x)}{\sin x(\cos x-\sin x)}

=\dfrac{\cos x}{\sin x}

=\dfrac{\csc x}{\sec x}

###

13.

\dfrac{1+\tan x}{\sin x+\cos x}=\dfrac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}

=\dfrac{\cos x+\sin x}{\cos x(\sin x+\cos x)}

=\dfrac1{\cos x}

=\sec x

###

14.

\sin2x(\cot x+\tan x)=2\sin x\cos x\left(\dfrac{\cos x}{\sin x}+\dfrac{\sin x}{\cos x}\right)

=2\sin x\cos x\dfrac{\cos^2x+\sin^2x}{\sin x\cos x}

=2

###

15.

\dfrac{1-\tan^2\theta}{1+\tan^2\theta}=\dfrac{1-\frac{\sin^2\theta}{\cos^2\theta}}{1+\frac{\sin^2\theta}{\cos^2\theta}}

=\dfrac{\cos^2\theta-\sin^2\theta}{\cos^2\theta+\sin^2\theta}

=\cos2\theta

3 0
3 years ago
A rectangular prism has a length of 7 1/2 feet a width of 3 3/4 feet and a height of 2 feet what is the volume of the prism
RideAnS [48]
7 1/2 x 3 3/4 x 2, to get the answer. The answer is





56 1/4 feet squared

3 0
3 years ago
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