Let X= the number of tickets sold at $35 each
Let 350 -X = the number of tickets sold at $25 each
The number of tickets sold for each type will be computed as follows:
X(35)+(350-X)25=10250
35X+8750-25X=10250
10X=10250-8750
X=1500/10
X=150 the number of tickets sold at $35 each
350-150 the number of tickets sold at $25 each
To recheck:
150(35)+200(25)
5250+5000
10250
Answer:
Pierre has enough boards and nails to make 9 tables and 5 chairs.
Step-by-step explanation:
13T+8C ≤ 220
Let us substitute 9 for T and 5 for C and check.
13(9) + 8(5) = 117 + 40
= 157 < 220
So, 220 wooden boards are sufficient to make 9 tables and 5 chairs.
48T+37C ≤ 760
Substitute 9 for T and 5 for C.
48(9)+37(5) = 432 + 185
= 617 < 760
So, 760 nails are sufficient to make 9 tables and 5 chairs.
Hence, Pierre has enough boards and nails to make 9 tables and 5 chairs.
Answer:
n >_44
Step-by-step explanation:
1/2n>_22
(times 2 on both sides)
n >_44
*** >_ is greater than or equal to sign
-3+3x=-2(x+1)
First: I will get rid of the bracket:
-3+3x=-2x-2
Now, all the x goes to the left side, all the numbers without x to the right side:
3x+2x=-2+3
we add up"
5x=1
divide by 5:
