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zvonat [6]
3 years ago
15

What is the maximum value of the objective function, P, with the given constraints?

Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

P=20x+35y

Constraints,

x+y \leq 12

5x+y \leq 20\\x \geq 0\\y \geq 0

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

P=20x+35y

  • Point (0,0)

P=20(0)+35(0)=0

P=20x+35y

  • Point (0,12)

P=20(0)+35(12)=420

  • Point (2,10)

P=20(2)+35(10)=40+350=390

  • Point (4,0)

P=20(4)+35(0)=80

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

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Answer:

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Step-by-step explanation:

Data given and notation

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X=204 represent the people said that they recycled

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Concepts and formulas to use  

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Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.816 -0.7}{\sqrt{\frac{0.7(1-0.7)}{250}}}=4.002  

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It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

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