Question

If 40 Ps are needed, and on-hand inventory consists of 15 Ps and 10 each of all other components and subassemblies, how many Cs are needed

Answer 1

Answer:

350 units

Explanation:

The computation of the number of Cs is needed is shown below;

The requirement of Ps = 40

Ps still = 15

So, the Net of Ps needed is

=40 - 15

= 25

Bs needed for 25 units of P is

= 3 × 25

= 75

And, B units still = 10

So, the Net of B units needed is

= 75 - 10

= 65

So, Cs needed for 65 units of B is

= 4 × 65

= 260

Cs needed directly for every unit of P is

= 1 × 4

= 4

hence , total Cs needed for 25 units of P is

= 4 × 25

= 100

Now

Total Cs required is

= 260 + 100

= 360

And, C units still = 10

So, the Net Cs needed is

= 360 - 10

= 350 units