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oee [108]
3 years ago
12

craig spent $27 to buy 3 calendars. the next day, he spent another $18 for more calendars. Each calendar cost the same amount. H

ow many calendars did craig buy?
Mathematics
1 answer:
Maslowich3 years ago
8 0

Answer:

She bought 5 calendars.

Step-by-step explanation:

Let Craig bough x calendars.

The cost of 3 calendars is $27.

Hence, the cost of 1 calendar is 27/3 = $9

Now, it has been given that she spent another $18 for more calendars. And we have calculated that cost of 1 calendar is $9.

Hence, in $18 she could buy 2 more calendars.

Therefore, the number of calendars she bought is given by

3 + 2

= 5

She bought 5 calendars

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Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 16 + 2x − x^2, [0, 5]
RSB [31]

Answer:

<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>

Step-by-step explanation:

To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.

at x = 0;

f(0) =  16 + 2(0) − 0²

f(0) = 16

at the other end point i.e at x = 5;

f(5) =  16 + 2(5) − 5²

f(5) = 16 + 10-25

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The absolute minimum value is 1  and  occurs at x  = 5

The absolute maximum value is 16 and  occurs at x  = 0

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garik1379 [7]

Answer:

D.

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m =  \frac{3 - 0}{0 - 4.5}  =  \frac{3}{ - 4.5}  =  -  \frac{3}{ \frac{9}{2} }  =  -  \frac{2}{3}

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6.875

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