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oee [108]
3 years ago
12

craig spent $27 to buy 3 calendars. the next day, he spent another $18 for more calendars. Each calendar cost the same amount. H

ow many calendars did craig buy?
Mathematics
1 answer:
Maslowich3 years ago
8 0

Answer:

She bought 5 calendars.

Step-by-step explanation:

Let Craig bough x calendars.

The cost of 3 calendars is $27.

Hence, the cost of 1 calendar is 27/3 = $9

Now, it has been given that she spent another $18 for more calendars. And we have calculated that cost of 1 calendar is $9.

Hence, in $18 she could buy 2 more calendars.

Therefore, the number of calendars she bought is given by

3 + 2

= 5

She bought 5 calendars

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vladimir2022 [97]

Answer:

SOHCAHTOA.

TOA=opposite/adjacent.

Tan45=100/h.

h tan45=100.

h×1=100.

h=100m

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Debora [2.8K]

Answer:

P(success at first attempt) = 0.1353

Step-by-step explanation:

This question follows poisson distribution. Thus, the formula is;

P(k) = (e^(-G) × (G)k)/k!

where;

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Thus; number of frames generated in 50 ms is;

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To find the chance of success on the first attempt will be given by;

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8 0
3 years ago
A company makes electronic gadgets. One out of every 50 gadgets is faulty, but the company doesn't know which ones are faulty un
Talja [164]

Answer:

Yes, the company can expect a profit in the long term

Step-by-step explanation:

In this question, we are to project if a company is expected to make a profit or loss given the information in the question.

Let’s use the scenario of 50 gadgets produced.

1 is expected to be faulty, while 49 is thus expected to work perfectly.

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3 years ago
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kiruha [24]

Answer:

16 is correct

Step-by-step explanation:

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yarga [219]
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