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Orlov [11]
3 years ago
10

Find the complement of a 48° angle.

Mathematics
2 answers:
Troyanec [42]3 years ago
6 0

90-48=42

42 is the answer

xxTIMURxx [149]3 years ago
3 0

90 - 48 = 42 is the answer

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Angle AOD=69°
Evgesh-ka [11]

The value of <em>x</em> where by exterior angles theorem, ∠DCO equals 2·x, 69° equals the sum of ∠DCO and x° is <em>x </em>= 23°

<h3>What is the exterior angles theorem?</h3>

The exterior angles theorem states that the exterior angle of a triangle is equal to the sum of the opposite interior angles.

The given parameters are;

Points on the circle are; ABCD

Straight lines = AOBE and DCE

Segment CO = Segment CE

∠AOD = 69°

∠CEO = x°

∠OCD = ∠ODC base angles of isosceles triangle

69° = ∠x° + ∠ODC exterior angle of a triangle

∠DOC = 180 - 2×∠ODC (Angle sum property of a triangle)

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x° + 69° - 2×∠ODC = 0

∠ODC = 2·x° (exterior angle of a triangle is equal to the sum of the opposite interior angles)

69° = x° + ∠ODC = x° + 2·x° = 3·x° (substitution property of equality)

69° = 3·x°

x = 69° ÷ 3 = 23°

  • x = 23°

Learn more about angles in a triangle here:

brainly.com/question/25215131

#SPJ1

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