Answer:
the answer is in the link
Step-by-step explanation:
Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
X=-2
You can also check by plugging -2 in for x. Here is a picture. Please notify me if I made an error!
The approximate probability that the code only contains odd numbers is 0.02381.
〽Hola User_______________
⭐Here is Your Answer..!!!
______________________
↪Cartesian Coordinates of the system....!!
↪X = rcos⊙ and Y = rsin⊙
↪since here Radius (r) = 10 units and Theta (⊙) = 225°
↪there fore substituting we get as ..
↪X = 10 ( cos 225° ) = 10 * -1/ root 2 = -7.071
↪Y = 10 ( sin 225° ) = 10 * -1/root2 = = -7.071
↪the cordinates are as follows
↪(x,y) = (-7.071, -7.071 )
