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FromTheMoon [43]
4 years ago
5

7 x -5/9 HELP PLEASE

Mathematics
2 answers:
JulsSmile [24]4 years ago
4 0
3.89 but 8 is repeating
Lana71 [14]4 years ago
4 0

Answer:

- 35/9

Step-by-step explanation:

Hello! Thanks for letting me answer your question! If you have any more questions feel free to ask me! If not, Have a WONDERFUL day and Please don't forget to consider making me Brainliest on your question today!

Btw i like your name XD

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The formula for the volume of a pyramid is V=(1/3) ⁢B⁢h, where B is the area of the base and h is the height. Rearrange the form
PIT_PIT [208]
To make an equation that solves for the height as according to the volume of a pyramid, you must isolate the variable h on one side.

The first thing you have to do is to multiply both sides by 3 to get 3V=Bh.

Then, divide both sides by B to get your answer as h=3V/B.
6 0
3 years ago
X + 5y = 8<br> -x + 2y = -1<br> How is this solved?
Oksi-84 [34.3K]
Add both the equations together to eliminate x

x+5y=8
-x+2y=-1

7y=7
y=1

Now fill in y into the original equation

x+5(1)=8
x+5=8
x=3

Now you can check by filling x and y into the second equation.

-(3)+2(1)=-1
-3+2=-1
-1=-1

So your answer will be (3, 1)

Brainliest my answer if it helps you out?
8 0
3 years ago
Does anyone mind helping?
lorasvet [3.4K]

Answer:

x^2  y^12

Step-by-step explanation:

( x ^ 1/2 * y ^3 ) ^ 4

A power raised to a power has the exponents multiplied

a^b^c = a^ (b*c)

x^ 1/2 ^ 4  * y^3^4

x^(1/2*4)  * y^(3*4)

x^2  y^12

6 0
3 years ago
Read 2 more answers
a prepaid phone card purchased at phone ahead an airport franchise costs 7.50 for 60 minutes. find the cost per minute
Minchanka [31]

Answer:

$.125

Step-by-step explanation:

60 minutes = 1 hour

60 minutes for $7.50

So, $7.50/60 = $0.125

5 0
3 years ago
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Standardization of Normal Distribution is the process of
n200080 [17]

Answer:

Step-by-step explanation:

Standardizing a normal distribution is to convert a normal distribution to the standard normal distribution. In real-world applications, a continuous random variable may have a normal distribution with a value of the mean that is different from 0 and a value of the standard deviation that is different from 1.

7 0
3 years ago
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