What is the answers to 3.5 applied statistics

The ratio of the geometric mean and arithmetic mean of two numbers is 3:5, find the ratio of the smaller number to the larger nu

IgorC [24]

Answer:

$\frac{1}{9}$

Step-by-step explanation:

Let the numbers be x,y, where x>y

The geometric mean is

$\sqrt{xy}$

The Arithmetic mean is

$\frac{x + y}{2}$

The ratio of the geometric mean and arithmetic mean of two numbers is 3:5.

$\frac{ \sqrt{xy} }{ \frac{x + y}{2} } = \frac{3}{5}$

We can write the equation;

$\sqrt{xy} = 3$

or

$xy = 9 - - - (2)$

l

and

$\frac{x + y}{2} = 5$

or

$x + y = 10 - - - (2)$

Make y the subject in equation 2

$y = 10 - x - - - (3)$

Put equation 3 in 1

$x(10 - x) = 9$

$10x - {x}^{2} = 9$

${x}^{2} - 10x + 9 = 0$

$(x - 9)(x - 1) = 0$

$x =1 \: or \: 9$

When x=1, y=10-1=9

When x=9, y=10-9=1

Therefore x=9, and y=1

The ratio of the smaller number to the larger number is

$\frac{1}{9}$

3 0

2 years ago

Will give brainliest if right, please help me with my homework

Rus_ich [418]

Answer:

Step-by-step explanation:

um

6 0

3 years ago

emily has saved 75.25 so far for a new phone. the cell phone that she want costs 102.19 How much more money does she need to pur

Alenkinab [10]

Answer:

emily has saved 75.25 so far for a new phone. the cell phone that she want costs 102.19

How much more money does she need to purchase a phone?

The Correct Answer Is $ 26.94

xXxAnimexXx

Have a great day!

6 0

2 years ago

The volume of a box V is given by the formula V=lwh, where l is length, w Is width, and h is height.

Nana76 [90]

1)Original Equation: V=lwh
Divide by lw: V/w=lw/lw(h)
Answer: h= V/lw

2)Set up the equation as V=lwh
Substitute the variables for numbers: 50=10(2)h
Multiply 10*2: 50=20h
Divide 50each side by 20 to get rid of 20h: 50/20=20/20
H=2.5
The height of the box is 2.5 meters tall.

7 0

3 years ago

Read 2 more answers

Use the given minimum and maximum data entries, and the number of classes, to find the class width, the lower class limits,

Gennadij [26K]

Using proportions and the information given, it is found that:

The class width is of 14.375.

The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.

The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

Minimum value is 19.
Maximum value is of 134.
There are 8 classes.
The classes are all of equal width, thus the width is of:

$W = \frac{134 - 19}{8} = 14.375$

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.

The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0

3 years ago