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3 years ago

If c is positive and b is negative, what two signs would you use?

Mathematics

1 answer:

Artyom0805 [142]3 years ago

4 0

- and + Be more specific for a better answer also provide a picture

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Compare using >, <, or =.<br> -36/8________- 4.5

Feliz [49]

Answer:

Step-by-step explanation:

to find whether -36/8 is greater than, less than, or equal to is -4.5, we must first solve -36/8.

-36/8 = -4.5

So the answer is -4.5 = -4.5

Hope that helps!

5 0

2 years ago

Read 2 more answers

A portion of the Quadratic Formula proof is shown. Fill in the missing statement.

Zielflug [23.3K]

Answer:

Option A.

Step-by-step explanation:

we have

$x+\frac{b}{2a} =\pm\sqrt{\frac{b^2-4ac}{4a^2}}$

Simplify the right side of the equation

we know that

$\pm\sqrt{\frac{b^2-4ac}{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{\sqrt{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{2a}$

The expression is

$x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}$

therefore

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

4 0

2 years ago

Please help me !!!!!

romanna [79]

Answer:

3/8

Step-by-step explanation:

If 1 and 3 are odd numbers then all you have to do is count the number of 1 and 3's(3). then count the number of numbers (8).

3 0

2 years ago

Rachel bought 7 cookies and 5 muffins. The equation 7c+5m=10.45 represents the amount of money she spent. Jack bought 3 cookies

malfutka [58]

M=1.25
c=0.6
I got this by creating a systems of equations and I used the substitution method

4 0

2 years ago

A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced; then

jarptica [38.1K]

Answer:

$\frac{2}{15}$

Step-by-step explanation:

GIVEN: A bag contain $5$ red marbles, $4$ green marbles and $1$ blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.

TO FIND: What is the probability both marbles are green.

SOLUTION:

Total marbles in bag $=10$

total number of green marbles $=4$

Probability that first marble will be green $P(A)=\frac{\text{total green marbles}}{\text{total marbles}}$

$=\frac{4}{10}=\frac{2}{5}$

Probability that second marble will be green $P(B)=\frac{\text{total green marble in bag}}{\text{total marble in bag}}$

$\frac{3}{9}=\frac{1}{3}$

As both events are disjoint

probability both marbles are green $=P(A)\times P(B)$

$=\frac{2}{5}\times\frac{1}{3}=\frac{2}{15}$

Hence the probability both marbles are green is $\frac{2}{15}$

8 0

2 years ago