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Julli [10]
3 years ago
9

Hey guys, I need some help. Would appreciate it.

Mathematics
1 answer:
34kurt3 years ago
7 0

the 3th choice because it does not add up to 180, it actually adds up to something greater

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Please help with triangles
Slav-nsk [51]
The first is a right triangle because there is a right angle, and it is scalene because none of the sides are congruent.

The second is an obtuse triangle because there is an obtuse angle, and it is an isosceles triangle because two of the sides are congruent.

The third is an acute triangle because all of the angles are acute, and it is an <span>isosceles triangle because two of the sides are congruent.

The fourth is a right triangle because it has a right angle, and it is a s</span><span>calene because none of the sides are congruent.</span>
8 0
3 years ago
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Find a vector function, r(t), that represents the curve of intersection of the two surfaces. the paraboloid z = 9x2 y2 and the p
dolphi86 [110]

The vector function is, r(t) =  \bold{ < t,2t^2,9t^2+4t^4 > }

Given two surfaces for which the vector function corresponding to the intersection of the two need to be found.

First surface is the paraboloid, z=9x^2+y^2

Second equation is of the parabolic cylinder, y=2x^2

Now to find the intersection of these surfaces, we change these equations into its parametrical representations.

Let x = t

Then, from the equation of parabolic cylinder,  y=2t^2.

Now substituting x and y into the equation of the paraboloid, we get,

z=9t^2+(2t^2)^2 = 9t^2+4t^4

Now the vector function, r(t) = <x, y, z>

So r(t) = \bold{ < t,2t^2,9t^2+4t^4 > }

Learn more about vector functions at brainly.com/question/28479805

#SPJ4

7 0
2 years ago
What percent of classes have at least 21 students first block brainly
skad [1K]
Wait do they actually?
6 0
3 years ago
The system of equations y = one-fourth x minus 1 and y = negative one-half x minus one-fourth is shown on the graph below. On a
love history [14]

Step-by-step explanation:

<u>Step 1:  Convert into expressions</u>

y = one-fourth x minus 1 → y = \frac{1}{4}x-1

y = negative one-half x minus one-fourth → y = -\frac{1}{2}x - \frac{1}{4}

They intersect at (1, -\frac{3}{4})

Answer: Option A, (1, negative three-fourths)

8 0
3 years ago
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I need help its my homework and it's due today<br>Find the base angles.​
MrRa [10]

Answer:

Each base angle would be 70°.

Step-by-step explanation:

<em>*</em><em>Base angles means the two equal angles formed on the base are called base angles.</em>

<em> </em><em>B</em><em>ase means the third unequal side of the triangle.</em><em> </em><em>*</em>

Given triangle is isosceles triangle.

The angle of vertex which is given is <u>40°</u>.

Let each base angle be <em>x</em>.

We know that,

<em>There are two base angles in a isosceles triangle</em>.

And, Sum of angles of triangle is 180° .

Therefore,

\tt \implies \: x + x   + 40 {}^{ \circ}  = 180 {}^\circ

Now Solve For <em>x</em>. That would be the solution.

Steps:

<u>Combine like terms:</u>

\tt \implies2x + 40{}^{ \circ}  = 180{}^{ \circ}

<u>Subtract 40 from both sides:</u>

\tt \implies2x + 40{}^{ \circ}  - 40 = 180{}^{ \circ}   - 40{}^{ \circ}

<u>Simplify </u><u>the</u><u> </u><u>LHS </u><u>and </u><u>RHS</u><u>:</u>

\tt \implies2x + 0 = 140{}^{ \circ}

\tt \implies2x = 140 {}^{ \circ}

<u>Divide both sides by 2:</u>

\tt \implies \cfrac{2x}{2}  =  \cfrac{140{}^{ \circ} }{2{}^{ \circ} }

<u>Use cancellation method and cancel LHS and RHS:</u>

\tt \implies  \cfrac{ \cancel2x}{ \cancel2}  =  \cfrac{ \cancel{140^{ \circ}} }{ \cancel{2{}^{ \circ} }}

\tt \implies \cfrac{1x}{1}  =  \cfrac{70{}^{ \circ} }{1{}^{ \circ} }

\tt \implies{1x}  = {70}^{ \circ}

\tt \implies{x} = 70{}^{ \circ}

Hence, each base angle would be 70°.

<u>Verification</u>:

As we know that sum of angles of triangle is 180°.

So,

\tt \implies \: Base \:  angle + other \:  base \:  angle  + vertex \: angle= 180{}^{ \circ}

We got that one base angles of the given isosceles triangle is 70° and other is 70°, and the vertex angle is 40°[Given].

\tt \implies70{}^{ \circ}  + 70{}^{ \circ}  + 40{}^{ \circ}  = 180{}^{ \circ}

<u>Solve it.</u>

\tt \implies140{}^{ \circ}  + 40{}^{ \circ}  = 180{}^{ \circ}

\tt \implies180{}^{ \circ}   = 180{}^{ \circ}

\tt \: LHS  = RHS

\star \sf \: Hence, Verified.

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

4 0
2 years ago
Read 2 more answers
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