What are the solutions to x2+14x+40=0

Mathematics

1 answer:

torisob [31]3 years ago

7 0

Answer:x

2−14x+40=0 Factor x2−14x+40 using the AC method.(x−10)(x−4)

0 If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.x−10=0x−4=0 Set the first factor equal to 0 and solve.x=10Set the next factor equal to 0and solve....x=4

The final solution is all the values that make (x−10)(x−4)=0 true x=10,4

Step-by-step explanation:IDK

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Consider the sequence: 3, 8, 13, 18, 23, ...The recursive formula for this sequence is:an = an-1 + 5In a COMPLETE sentence, expl

Akimi4 [234]

Answer:

$a_8=38$

Step-by-step explanation:

Recursive sequence

In a recursive sequence formula, each term $a_n$ is computed as a function of one or more previous terms. In the formula

$a_n=a_{n-1}+5$

n is the number of the term we want to calculate. If n=8, then the formula becomes

$a_8=a_{7}+5$

We can see $a_{n-1}$ is the previous term. It means we need $a_7$ to be able to compute $a_8$ . But we also need $a_6$ to compute $a_7$ and so on until some known data is reached. The question provides five terms, $a_5=23.$