Answer:
area (A) =(9x+108)unit^2
perimeter (P) =(2x+42) units
Step-by-step explanation:
area(A) =length(l) × breadth(b)
perimeter(P) =2(l+ b) {which is sum of all sides}
so, l = 7+x+5 = (x+12) units and b = 9 units
now, A=(x+12) × 9 units^2
=(9×x + 12×9 ) units^2
Therefore,
A =(9x+108)unit^2
next, P=2{(x+12)+9}
=2(x+21)
Hence,
P=(2x+42) units
First problem:
cos (theta)=1
Using the inverse cosine function, you get theta = 0.
Now we find tan 0 = 0
cot(theta) = 1/tan(theta) = 1/0
Division by zero is undefined, so the answer is d. undefined
Second problem:
cos (theta)=1
Use the inverse cosine function.
theta = 0°
Answer: c. 0°
It would be E) nothing, since it would be 289.82
Answer:
The answer is below
Step-by-step explanation:
The question is not complete. The complete question is:
The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.
Solution:
Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:
sin θ = opposite / hypotenuse
Using trigonometric identities, we can get that:
sin(30) = x / 12
This gives:
0.5 = x / 12
Cross multiplying the terms to get:
x = 12 * 0.5
x = 6 ft
Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.
Answer: first, Nolan must substitute 23 for J To simplify, Nolan must subtract 16 form 23. 23 is a solution of the equation.
Step-by-step explanation: