The value is 1.1. Because it is 1.1 spaces away. the negative symbol isn’t,t important in this case.
Answer:
I'm sorry I can help you maybe a little bit if that's okay. Btw what grade are you in?
Step-by-step explanation:
First year: the depreciation is (35/100) x 20000 = £7000; now the value of the car is £20000 - £7000 = £13000;
Second year: the depreciation is (35/100) x 13000 = £4550; the current value of the car is £13000 - £4550 = £8450.
-1 = (x-1)/3
(multiply both sides by 3)
-3 = x-1
(add 1 on both sides)
x=-2
T= sqrt(5/wc)
remove ( )
T= 5sqrt/wc
multiply by wc
Twc=5sqrt
divide by Tc
W= 5sqrt/cT
hope this helps
