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Dima020 [189]
3 years ago
14

Einsteinium-253253253 is an element that loses about \dfrac23

Mathematics
2 answers:
yan [13]3 years ago
5 0

Answer:

S(t) = 450 (1/3)^t .

Step-by-step explanation:

Sedbober [7]3 years ago
4 0

Answer:

                         S(t)=450\times(1/3)^t

Explanation:

The element is <em>einstenium-253</em>. That means that the mass number, i.e. numbrer of protons plus neutrons, of this isotope is 253, but that is not relevant to answer the question.

It is said that the element <em>loses about 2/3 of its mass every month, </em>then to find the remaining amount, every month you have to multiply by 1/3.

With that you can create a decaying function that gives a sample's mass in grams:

         

        Initial\text{ }mass=M_0\\ \\ Mass\text{ }after\text{ }1\text{ }month=M_0\times1/3\\ \\  Mass\text{ }after\text{ }2\text{ }months=M_0\times(1/3)^2\\ \\  Mass\text{ }after\text{ }3\text{ }months=M_0\times(1/3)^3\\ \\  Mass\text{ }after\text{ }t\text{ }months=M_0\times(1/3)^t

Now you can replace the initial mass with 450 g and write the specific function for this sample:

          S(t)=450\times(1/3)^t

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just olya [345]
∠BDC=30, so ∠CBD + ∠BCD=180-30=150
ΔDBC is isosceles, so ∠CBD=∠BCD=half of 150=75
∠ABC=∠ABD-∠CBD=155-75=80
ΔABC is isosceles, so ∠ABC=∠ACB=80
∠BAC=180-80-80=20
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4 years ago
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grandymaker [24]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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8 0
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Hope this helps you

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