The GCF of 20x^4 and 6x^3 would be " 2x^3 "
Answer:
Step-by-step explanation:
complimentary angles, when added = 90 degrees
69 + 5n + 1 = 90
5n + 70 = 90
5n = 90 - 70
5n = 20
n = 20/5
n = 4 <====
Y≤x/3-1 AND y≤x/3-3
So for BOTH inequalities to be true:
y≤x/3-3
Answer:
umm what or we doing?
Step-by-step explanation:
The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6
Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
(-2,6) ---> (-2-2, 6-16) = (-4,-10)
P = (-2,6)
P ' = (-4,-10)
The answer is -10 because your teacher just wants the y coordinate of point P'
