Answer
By using the exterior angle property
The measure of exterior angle is equal to the sum of two opposite interior angles.
In ∠QSR is exterior angle.
∠SPQ and ∠SQP are the opposite interior angle of the exterior angle ∠QSR .
Thus
∠QSR = ∠SPQ + ∠SQP
As given in the diagram
∠QSR = 2x , ∠SQP = x
Put in the above
2x = x + ∠SQP
∠SQP = 2x - x
∠SQP = x
Thus
∠SPQ = ∠SQP = x
By using the property
if two angles are equal in a triangle than their opposite sides are also equal .
Thus
PS = SQ
Two sides of triangle are equal .
therefore Δ PQS is a isosceles triangle .
Answer:
Tn=12n(n+1)
Step-by-step explanation:
Explanation:
These are the triangular numbers - each term in the sequence being the sum of the first n positive integers:
T1=1=1
T2=3=1+2
T3=6=1+2+3
etc.
Notice that:
2Tn=(0)+1+(0)+2+...+(n−1)+(0)+n
2Tn+(0)+n+(n−1)+...+(0)+2+(0)+1
2Tn=(n+1)+(n+1)+...+(n+1)+(n+1)
2Tn=n(n+1)
So:
Tn=12n(n+1)
Answer:do h just want answer or explanation
Step-by-step explanation:?
Answer:
Each boy recieved $25.25 each
Step-by-step explanation:
First, you add up all the money the 3 boys spent.
15+15+15=45
Then you add the sum of the equation to the amount all the boys had afterward.
45+30.75=75.75
Finally, you divide that product to 3 boys.
75.75/3=25.25
Therfore the answer is $25.25 each.
Answer:
Since the price is given by an exponential function, the decline in price is exponential.
The component will cost $36.8475 in three years.
Step-by-step explanation:
The equation for the price of a component has the following format:

In which P(t) is the price after t years, P(0) is the initial price, and r is the rate that the price decreases.
Since the price is given by an exponential function, the decline in price is exponential.
The price of a computer component is decreasing at a rate of 15% per year.
This means that 
Component costs $60 today
So P(0) = 60. Then



What will it cost in three years?
This is P(3).


The component will cost $36.8475 in three years.