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ohaa [14]
3 years ago
5

What is the result of isolating x^2 in the equation below (x+1)^2+(y-8)^2=9

Mathematics
2 answers:
taurus [48]3 years ago
8 0

Answer:

x² = 8 - (y - 8)² - 2x

x² = 16y - y² - 2x - 56

Step-by-step explanation:

∵ (x + 1)² + (y - 8)² = 9

∵ x² + 2x + 1 = 9 - (y - 8)²

∴ x² = 9 - (y - 8)² - 2x - 1

∴ x² = 8 - (y - 8)² - 2x

OR:

∵ x² = 8 - (y² -16y + 64) - 2x

∴ x² = 8 - y² + 16y - 64 - 2x

∴ x² = 16y - y² - 2x - 56

jeka943 years ago
3 0

Answer:

x² = 16y-y²-2x-56

Step-by-step explanation:

We have given the equation:

(x+1)²+(y-8)²=9

We have to solve it for x².

So, the above equation is:

(x+1)²+(y-8)²=9

Open the square of  the terms we get,

x²+1+2x+y²+64-16y = 9

x²+2x+y²-16y+65 = 9

The  equation in terms of x² is:

x²= 9-2x-y²+16y-65

x² = 16y-y²-2x-56 is the answer.

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