Mr Anderson wrote 7×9×10.3

6.3 x 10^14<br><img src="https://tex.z-dn.net/?f=6.3%20%5Ctimes%20%20%7B10%7D%5E%7B14%3F%7D%20" id="TexFormula1" title="6.3 \tim

Nutka1998 [239]

I'm assuming you're looking to find the expanded form of the number?

This number is in scientific notation. The easiest way to convert it to a normal number is to move the decimal place 14 to the right. I've attached a picture showing how to do this. You should get 630,000,000,000,000

There's a faster way to do this - notice that you need to move the decimal 14 to the right, and there's one number already after the decimal place. Therefore, 13 places will be filled with zeros. So, just write out 63 and add 13 zeros.

For more general help on scientific notation, check out these videos: https://www.khanacademy.org/math/pre-algebra/pre-algebra-exponents-radicals/pre-algebra-scientific-notation/v/scientific-notation-old

Hope that helps! Feel free to message me or leave a comment if I can clarify anything :)

7 0

3 years ago

Jason ran 325 meters farther than Kim ran. Kim ran 4.2 kilometers. how many meters did Jason run?

notka56 [123]

4200= 4.2 km so
4200 + 325= 4525 meters
jason ran 4525 meters

6 0

3 years ago

42:28

gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) $\overline{ED}\cong \overline{FD}$

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

$\\ \overline{EF}\cong \overline{FD}$ (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD = 60°

ΔEFD is an equilateral triangle as all interior angles are equal

$\\ \overline{EF}\cong \overline{FD}\cong \overline{ED}$ (definition of equilateral triangle)

$\overline{ED}\cong \overline{FD}$

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

$\overline{CF}\cong \overline{CD}$ (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0

3 years ago

URGENT i need the answer for number 23 tyyyy

kupik [55]

No your friend I’d not correct although the slope is 4, the y-intercept is -3 because of the minus 3 in the equation.

4 0

3 years ago

Read 2 more answers

Two cars leave town at the same time and travel in opposite directions. Speed of car A is 12 km/h more than car B. They are 312k

Zina [86]

Answer:

Speed of car B is 33 km/h and speed of car A is $45\,\,km/h$

Step-by-step explanation:

Let speed of car B be $x$ km/h

Speed of car A is 12 km/h more than car B.

Therefore,

Speed of car A = $(12+x)$ km/h

Distance = Speed × Time

Distance travelled by car A in 4 hours = $4(12+x)$ km = $(48+4x)$ km

Distance travelled by car B in 4 hours = $4x$ km

Also, cars A and B are 312km apart after 4 hours.

$48+4x+4x=312\\48+8x=312\\8x=264\\\\x=\frac{264}{8}\\\\x=33\,\,km/h$

Speed of car B is 33 km/h and speed of car A is $12+x=12+33=45\,\,km/h$

5 0

3 years ago