Question

An opaque bag contains 5 green marbles 3 blue marbles and 2 red marbles. If a marble is drawn at random what are the odds of drawing a blue marble?

Answer 1

Answer:

Odds are 3 to 7

Step-by-step explanation:

The odds are defined as the probability that the event will occur divided by the probability that the event will not occur.

Let's find:

Probability of blue marble = 3/10 [ 3 blue and 10 in total]

Probabilty of NOT blue marble = 7/10 [7 marbles are red and green (not blue) and 10 in total]

Hence,

Odds of drawing a blue marble = $\frac{\frac{3}{10}}{\frac{7}{10}}=\frac{3}{10}*\frac{10}{7}=\frac{3}{7}$

The odds are 3 to 7