Question

What is the factored form of 6n4 – 24n3 + 18n?

Answer 1

Answer:

= 6n(n^3 - 4n^2 + 3)

Step-by-step explanation:

6n^4 – 24n^3 + 18n

= 6n(n^3 - 4n^2 + 3)

Answer 2

Answer:

The factored form is : $6n(n-1)(n^{2}-3n-3)$

Step-by-step explanation:

The given expression is :

$6n^{4} -24n^{3} +18n$

Taking out 6n out as 6n is common for all, we get

$6n(n^{3} -4n^{2} +3)$

Now lets factor $n^{3} -4n^{2} +3$ by hit and trial method.

Putting n=1

Now, by hit and trial method, we put n=1,

p(n)= $1^{3} -4(1)^{2} +3$

=> p(1) = $1-4+3=0$

So, (n-1) is a factor.

Now, dividing $n^{3} -4n^{2} +3$ by n-1 we get $n^{2}-3n-3$

Therefore, the factored form is = $6n(n-1)(n^{2}-3n-3)$