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forsale [732]
3 years ago
9

What is the mid point of coordinates (-4, -5) and (6, 3)

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

(3, 0.5)

I hope this helps!

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12430000 in expanded form
Tresset [83]
10,000,000 + 2,000,000 + 400,000 + 30,000
4 0
3 years ago
What is the product of 2p+q and -3q-6p+1
Arlecino [84]

Hey there,

The question is to find the product of the two factors (2p + q)(-3q - 6p + 1).

Now we just multiply across:

  • -6pq - 12p² + 2p -3q²- 6pq + q

Now we combine like terms:

  • -12p² - 3q² + 2p + q

So the result would be -12p² - 3q² + 2p + q.

Hope I helped,

Amna

4 0
3 years ago
What is the solution to the equation 6x = 39?
SashulF [63]

Answer:

6.5

Step-by-step explanation:

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8 0
4 years ago
What is the answer to 3×2/3
dalvyx [7]
<h2><em>PEMDAS</em></h2><h2><em>Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction. Use this for the Order in which you do the work,</em></h2><h2><em>3 x 2 = 6. 6 / 3 = 2. 2 is your Answer. You could have done that with a calculator.</em></h2>
7 0
3 years ago
Read 2 more answers
Prove: Every point of S=(0, 1) is an interior point of S.
myrzilka [38]

Answer:

Proved

Step-by-step explanation:

To prove that every point in the open interval (0,1) is an interior point of S

This we can prove by contradiction method.

Let, if possible c be a point in the interval which is not an interior point.

Then c has a neighbourhood which contains atleast one point not in (0,1)

Let d be the point which is in neighbourhood of c but not in S(0,1)

Then the points between c and d would be either in (0,1) or not in (0,1)

If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.

Then we find that dn is a boundary point of S

But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.

Every point of S=(0, 1) is an interior point of S.

3 0
3 years ago
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