Answer:
6(1-5m) = 6
−
30
m
3(4+3r) = 12
+
9
r
3(6r+8) = 18
r
+
24
4(811+ 1+2) = 3256
-(-2-n) 7) = 14
+
7
n
-6(7k+11) = −
42
k
−
66
-3(71+1) = −
216
-6(1 +116) = −
702
-10(a - 5) = −
10
a
+
50
-3(1 + 2v) = −
3
−
6
v
-4(3r+2) = −
12
r
−
8
(3 - 76)-2 = −
75
(-2018x+20) = −
2018
x
+
20
(7 + 190)-15 = 182
(x + 1)14 = 14
x
+
14
The sequence is 4, 5, 6, 7, 8, ..... The pattern is: Each term is (the term before it) plus (1).
7/12 u need to multiply 3*4 and u keep the numerator the same
This is a permutations problem. There are only 7 comics you can move into different time slots, the 8th one being fixed in that last position. So you can look at it this way:
For the 1st position, you can choose from all 7 people. Once you've picked that one, you have 6 people to choose from for the 2nd position, and similarly for the remaining ones . This gives you 7x6x5x4x3x2x1 = 5040 ways to arrange them. And the last comic stays in the same position all the time so does not change this number. Make sense? If you need to demonstrate it to yourself, use a smaller number of comics, like 3 or 4, and write out the combinations to see that it works.
Step-by-step explanation:
In this case, you input the value of y (y = 6) into the equation ( 2.5(y-x)= 0)
2.5(6-x) = 0
Open the bracket,
(2.5×6)-2.5x= 0
Collect like terms.
2.5x= 2.5×6
Divide both sides by the coefficient of x (2.5)
x = 6
So,
x= 6 is true.
.
Substituting 6 for x in the equation,
2.5(6-6)= 0
2.5•0 = 0
0= 0
Which is also true.
