Answer:
th part of the field is covered in the second sprint.
Step-by-step explanation:
A football player is running the length of a 100 yard long football field.
Let player sprints x yards with the speed = 2 yards per second.
So time taken to cover x yards player will take time = 
seconds
Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = 
= 
seconds
Now total time taken by the player can be represented by the equation
Now we can solve this equation for the value of x.
x + 100 = 40×4
x + 100 = 160
x = 160 - 100 = 60 yards
And length of the second part will be = 100 - 60 = 40 yards
Now the fraction of the field covered by the player in second sprint will be
= 
= or 40%
Therefore, th part of the field was covered in second sprint.
The answer is 15
these chords are congruent because the radius of the circle are perpendicular to the them
so we can find EF by making an equation:
so EF is = 3(15)+5=50
good luck
Answer:
1) 20.9
2) 896
3) 21
Step-by-step explanation:
1) 5.6÷2^3+(12.75+7.45)
---> 12.75 + 7.45 = 20.2
÷ 
--> Simplify 2^3 to 8
÷ 8 + 20.2
--> 5.6 ÷ 8 = 0.7
--> Simplify
2) 4^3 × (0.6 +3.6) ÷ 0.3
---> 0.6 + 3.6 = 4.2
4^3 * 4.2 ÷ 0.3
---> 4^3 = 64
64 * 4.2 ÷ 0.3
--> 64 * 4.2 = 268.8
268.8 ÷ 0.3
--> 268.8 ÷ 0.3 = 896
896
3) 2^4 + (2.75 +1.75) ÷ 0.9
--> 2.75 + 1.75 = 4.5
2^4 + 4.5 ÷ 0.9
--> 2^4 = 16
16 + 4.5 ÷ 0.9
--> 4.5 ÷ 0.89 = 5
16 + 5
--> Simplify
= 21
Answer:
Hiii the answer would be a= -4b+8/3
Answer:
5
Step-by-step explanation:
(-3)(2)-7(-3)-10
-6+21-10
15-10
5
