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pogonyaev
4 years ago
10

PLEASEE HELPPPP

Mathematics
2 answers:
Allisa [31]4 years ago
5 0

Answer:

c would be ur answer for this problem yup thank me give me five stars and mark me brainlyest plz

Step-by-step explanation:


klemol [59]4 years ago
5 0

Answer:

it's d

Step-by-step explanation:

usatestprep

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dmitriy555 [2]

{303}^{9}   \times  {303}^{9}  \\  =  {303}^{9 + 9}  \\  =  {303}^{18}

<u>Answer</u><u>:</u>

<u>{303}^{18}</u>

<u>Hope </u><u>you</u><u> could</u><u> get</u><u> an</u><u> idea</u><u> from</u><u> here</u><u>.</u>

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6 0
3 years ago
I am unsure of the answer
timurjin [86]
Shifting a graph down by 5 units is the same as subtracting 5 from the right side. So, k is 5.
3 0
4 years ago
Solve 2x – 5 = 7?<br> What is the answer?
oksano4ka [1.4K]

Answer:

x = 6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Round to the nearest tenth
Vitek1552 [10]

<em>Note: I am assuming we have to determine the angle 'Ф'.</em>

Answer:

The value of Ф = 22.6°

Step-by-step explanation:

Given

hypotenuse = 13

To determine:

Angle = Ф = ?

Using the trigonometric ratio

cos Ф = adjacent / hypotenuse

here

  • hypotenuse = 13
  • Adjacent to Ф = 12

so substituting adjacent = 12, hypotenuse = 13 in the equation

cos Ф = adjacent / hypotenuse

cos Ф = 12 / 13

Ф = arccos (12/13)

Ф = 22.6°

Therefore, the value of Ф = 22.6°

8 0
3 years ago
Find the derivative of ((t^4-6)^3)*((t^3+6)^4)
rjkz [21]
=d/dx((t^4-6)^3) * (t^3+6)^4 + d/dx((t^3+6)^4) * (t^4-6)^3
=3*(t^4-6)^2 * (t^3+6)^4 * d/dx(t^4-6) + 4*(t^3+6)^3 * (t^4-6)^3 * d/dx(t^3+6)
=3*(t^4-6)^2 * (t^3+6)^4 * 4t^3 + 4*(t^3+6)^3 * (t^4-6)^3 * 3t^2
Simplify that if youd like
8 0
4 years ago
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