Answer:
a_{n} = a_{1} + (n-1)d
a_n = the nᵗʰ term in the sequence
a_1 = the first term in the sequence
d = the common difference between terms
The general term of an arithmetic sequence can be written in terms of its first term a1, common difference d, and index n as follows: an=a1+(n−1)d. ... The nth partial sum of an arithmetic sequence can be calculated using the first and last terms as follows: Sn=n(a1+an)2.
2[5+2(8-6)]
2[5+2(2)]
2[5+4]
2[9]
18
-90
Step-by-step explanation:
2/3x+4=3/5x-2
2/3x – 3/5x = -2 – 4
LCM for 5 & 3 is 15 so we can use it on the two fractions;
10/15x – 9/15x = 1/15 x
1/15x = -6
x = - 6 * 15
x = -90
Learn More:
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substitute the values for the letters
2(-17) = -34
3(-4) = -12
-34 - -12 = -34 +12 = -22
-22 is not greater than 12 so it is not a solution
