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geniusboy [140]
2 years ago
10

A 20 foot ladder leaning against a wall is used to reach a window that is 17 feet above the ground. How far from the wall is the

bottom of the ladder? Round to the nearest tenth of a foot.
Mathematics
1 answer:
GarryVolchara [31]2 years ago
8 0

The bottom of the ladder is 10.5 feet away from the wall

Step-by-step explanation:

The given scenario forms a right triangle.

Where

The length of ladder will be the hypotenuse

The wall on which the window is situated will ebt he perpendicular and

The distance between the foot of ladder and the wall will be the base

So,

Hypotenuse = H = 20 foot

Perpendicular = P = 17 feet

Base = B = ?

Using the Pythagoras theorem

H^2=P^2+B^2\\(20)^2=(17)^2+B^2\\400=289+B^2\\400-289=B^2\\B^2=111\\Taking\ square\ root\ on\ both\ sides\\\sqrt{B^2}=\sqrt{111}\\B=10.53\\Rounding\ off\ to\ the\ nearest\ tenth\\B=10.5

The bottom of the ladder is 10.5 feet away from the wall

Keywords: Triangle, Pythagoras Theorem

Learn more about Pythagoras theorem at:

  • brainly.com/question/9532142
  • brainly.com/question/9590016

#LearnwithBrainly

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Solve 2x^2+x-4=0<br> X^2+_×+_=0
natima [27]

Answer:

Hopes it helps

Step-by-step explanation:

The Quadratic Polynomial is

2 x² +x -4=0

Using the Determinant method to find the roots of this equation

For, the Quadratic equation , ax²+ b x+c=0

(b) x²+x=0

x × (x+1)=0

x=0  ∧ x+1=0

x=0     ∧   x= -1

You can look the problem in other way

the two Quadratic polynomials are

2 x²+x-4=0, ∧ x²+x=0

x²= -x

So, 2 x²+x-4=0,

→ -2 x+x-4=0

→ -x -4=0

→x= -4

∨

x² +x² +x-4=0

x²+0-4=0→→x²+x=0

→x²=4

x=√4

x=2 ∧ x=-2

As, you will put these values into the equation, you will find that these values does not satisfy both the equations.

So, there is no solution.

You can solve these two equation graphically also.

3 0
2 years ago
Please show your work this question what made you come to the conclusion. Thank you
AveGali [126]

Answer:

B the range, the x- and y-intercept

Step-by-step explanation:

the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.

the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)

3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

8 0
3 years ago
How many real solutions does the equation V2x + 4<br> = 3x + 1<br> have?
Verdich [7]

Answer:

5v^2x + 4

Step-by-step explanation:

I'm not sure but i hope this help's

3 0
2 years ago
Help will give Brainliest.
Luden [163]

no because you are not distributing numbers that multiply with each other and form new expressions

5 0
3 years ago
Read 2 more answers
Use substitution to determine which of the following points is a solution to the standard form equation below. 2y = 5
sashaice [31]
The question is incomplete.

This is the complete question as I found in internet:

<span>Use substitution to determine which of the following points is a solution to the standard form equation below 5x-2y = 10

these are the points:
</span>
-1,5

1,5

0,-5

0,5

Answer: (0, -5)

Explanation:


point          x           y        5x - 2y = 10 ?


-1,5         -1           5         5(-1) - 2(5) = - 5 - 10 = - 15 ≠ 10 ⇒ not a solution

1,5            1          5         5(1) - 2(5) = 5 - 10 = 5 ≠ 10 ⇒ not a solution
 
0,-5           0        -5           0 -2(-5) = 10 ⇒ a solution

0,5             0         5          0 - 2(5) = - 10 ≠ 10 ⇒ not a solution

7 0
3 years ago
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