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frosja888 [35]
3 years ago
10

What is 20 min ealy than 12:00

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
6 0

Answer:

11:40

Step-by-step explanation:

galina1969 [7]3 years ago
5 0

Answer:

11:40

Step-by-step explanation:

You can do 60-20 which is 40. Since you know there are 60 minutes in a hour, and you need 20 minutes earlier, you can subtract those which give you 40. Add 11 before it because you want to find 20 minutes earlier, which gives you 11:40.

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An element with mass 290 grams decays by 13.2% per minute. How much of the
Tatiana [17]

Answer:

FV=PV(1−d)^n

FV = 290(1-.132)^14

FV = 290(.868)^14

FV = 39.96 g

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
Write a system<br> of linear inequalities represented by the graph.
Helga [31]
2,3 or 4,1 either one
6 0
2 years ago
If f(x) = -7x+2 and g(x) = square root of x+3,<br> what is (fºg)(-2)?
Degger [83]

Answer:

(fog)(-2)=-5

Step-by-step explanation:

Given

f(x)= -7x+2

and

g(x)= √(x+3)

For finding (fog)(-2), we have to find (fog)(x) first

In order to find (fog)(x) we will put the value of g(x) in f(x) in place of x.

(fog)(x)= -7g(x)+2

Putting the value of g(x)  

(fog)(x)= -7√(x+3)+2

We have to find (fog)(-2), so we have to put at the place of x in the composition

(fog)(-2)= -7√(-2+3)+2

(fog)(-2)= -7√1+2

= -7(1)+2

= -7+2

=-5

So,

(fog)(-2)=-5

6 0
3 years ago
Read 2 more answers
Can someone explain how to solve this?
Dmitrij [34]

9514 1404 393

Answer:

  (2/3)(e^t +1)^(3/2)

Step-by-step explanation:

Use the substitution ...

  u = e^t +1

Then du = e^t and you are finding the integral of ...

  ∫u^(1/2)·du

which you know by the power rule is ...

  (2/3)u^(3/2) = (2/3)(e^t +1)^(3/2)

4 0
3 years ago
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