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ikadub [295]
3 years ago
15

A principal of $1900 was invested at 3.75% interest, compounded annually. Let be the number of years since the start of the inve

stment. Let y be the value of the investment, in dollars.
Write an exponential function showing the relationship between y and t?
Mathematics
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

y(t) = \$1900*1.0375^t

Step-by-step explanation:

If y is the future value of the $1900 investment, in dollars, after t years at a rate of 3.75% per year, compounded annually. The exponential function that describes the relationship between the variables y and t is:

y(t) = \$1900*(1.0375)^t

This relationship means that for every year t, the amount y will increase by a factor of 1.0375.

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Determine if the sequence below is arithmetic or geometric and determine the
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Answer: Arithmetic and 3

Step-by-step explanation:

12 - 9 = 3 9 - 6 = 3 The common difference is equal and is three and so it is an arithmetic sequence

12/9 = 4/3 9/6 = 3/2 The ratio is not equal so this is not a geometric sequence

4 0
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12 miles

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3 0
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Which ordered pairs are solutions to the inequality 4x+y>-6
Lilit [14]

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(-1.5, 0) and (0, -6)

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3 0
3 years ago
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Please help this is due tomorrow
mote1985 [20]

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8

Step-by-step explanation:

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7 0
3 years ago
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What is b1 and r of geometrical sequence if b3 −b1 = 16 and b5 −b3 = 144.
Naily [24]

Answer:

b1 = 2 ; r = 3

Step-by-step explanation:

Given that :

if b3 −b1 = 16 and b5 −b3 = 144.

For a geometric series :

Ist term = a

Second term = ar

3rd term = ar^2

4th term = ar^3

5th term = ar^4 ;...

If b3 - b1 = 16;

ar^2 - a = 16

a(r^2 - 1) = 16 - - - (1)

b5 - b3 = 144

ar^4 - ar^2 = 144

ar^2(r^2 - 1) = 144 - - - - (2)

Divide (1) by (2)

a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144

a / ar^2 = 1 / 9

ar^2 = 9a

Substitute for a in ar^2 - a = 16

9a - a = 16

8a = 16

a = 2

From ar^2 - a = 16

2r^2 - 2 = 16

2r^2 = 16 + 2

2r^2 = 18

r^2 = 18 / 2

r^2 = 9

r = √9

r = 3

Hence ;

a = b1 = 2 ; r = 3

7 0
3 years ago
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