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Svetach [21]
3 years ago
15

1 kg = ___ g A : 1 B : 10 C : 100 D : 1,000

Mathematics
1 answer:
zlopas [31]3 years ago
7 0
D: 1000 grams

thats the answer
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A surveyor wants to find the distance AB across a lake in the diagram. He locates a point C and the midpoints M and N of AC and
Gemiola [76]
AB = 56 because the bigger triangle is 2 times the smaller one.
5 0
3 years ago
What is the answer to this equation using the quadratic formula?<br> 3x^2+2x+4x=0
o-na [289]

~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{+4}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(4)}}{2(3)}\implies x=\cfrac{-2\pm \sqrt{4-48}}{6}

x=\cfrac{-2\pm \sqrt{-44}}{6}\implies x=\cfrac{-2\pm \sqrt{(-1)(2^2)(11)}}{6}\implies x=\cfrac{-2\pm 2~i\sqrt{11}}{6} \\\\\\ x=\cfrac{2(-1\pm i\sqrt{11})}{6}\implies x=\cfrac{-1\pm i \sqrt{11}}{3}

mind you that it has two complex roots, or imaginary values.

3 0
2 years ago
Angles of a triangle are in the ratio 2 : 4 : 3. Find the smallest angle of the triangle
3241004551 [841]

Answer:

Step-by-step explanation:

sum of all the angles in a triangle=180

let the angles be 2x, 4x and 3x

so, 2x+4x+3x=180

9x=180

x=20

so smallest angle 2x= 2(20)= 40 degrees

7 0
2 years ago
Read 2 more answers
Please help with either of these questions. Put the answer in the comments please
Lena [83]

Answer:

2) distance = 4 km

Displacement = 4 km east

3) distance = 35 km

Displacement = 5 km north

Step-by-step explanation:

2. He runs for 3 km in the east direction and then stops.. He now runs another 1 km in the same direction then stops.. Thus,

Total distance covered = 3 + 1 = 4 km

Total displacement is how far he is from his starting point = 3 + 1 = 4 km east

3) Runs 20km north and then runs 15 km back from starting point.

Thus;

Total distance covered = 20 + 15 = 35 km

Total displacement is distance from starting point = 20 - 15 = 5 km north

Subtracted because an opposite direction was taken after the 20km back to her starting point.

6 0
2 years ago
A 8-foot tall man is standing beside a 32-foot flagpole. The flagpole is
kipiarov [429]

Answer:

The flagpole's shadow is 16.875 feet longer than the man's shadow

Step-by-step explanation:

The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;

Height of the shadow=actual height of the flagpole×factor

where;

length of the flagpole's shadow=22.5 feet

actual height of the flagpole=32 feet

factor=f

replacing;

22.5=32×f

32 f=22.5

f=22.5/32

f=0.703125

Using this factor in the expression below;

Length of man's shadow=actual height of man×factor

where;

length of man's shadow=m

actual height of man=8 feet

factor=0.703125

replacing;

length of man's shadow=8×0.703125=5.625 feet

Determine how much longer the flagpole's shadow is as follows;

flagpoles shadow-man's shadow=22.5-5.625=16.875 feet

The flagpole's shadow is 16.875 feet longer than the man's shadow

7 0
3 years ago
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