Answer:
25%
Explanation:
In sheep, the allele for belly fur (A) is dominant to the allele for no belly fur (a). A mother with the genotype Aa and a father with the genotype Aa produce an offspring. What is the percent chance that the offspring will have NO belly fur?
Allele A is dominant over allele a.
Genotype of mother = Aa
Genotype of father = Aa
Crossing Aa and Aa:
Aa x Aa = AA, 2Aa, and aa
Since A is dominant over a, both AA and Aa have belly fur.
Hence, the ratio of the offspring with belly fur to those without belly fur is 3:1.
Percentage of the offspring without belly fur is 25%.