Answer:
a
Step-by-step explanation:
Answer:
They're the exact same, except for the variables.
Step-by-step explanation:
Since the variable can be any letter, it is the exact same equation but with different letters as x. Although the equation of G(y) has a y instead of x, you know y is the x and g(y) is the y because the y inside of the parentheses tells us that y is the independent variable.
Let me help you with this :)
John = x
Mike = y
x = 4 + 3y (4 more than 3 times)
x + y = 20 (we put the x above into this equation)
4 + 3y + y = 20
4y = 16 (we transfers the 4 on the left side to the right side and subtract it from the 20)
y = 4 (the answer is 4)
we use this for the equation:
x = 4 +3*4
x = 16
John is 16 years old and Mike is 4 years old :)
Could you get a closer picture?
5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N
Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
