In Mrs. Brown's Algebra class there are 15 boys and 10 girls. The students are presenting projects to the class. If Mrs. Brown s
elects students at random for presentations, what is the probability that the first student chosen is a girl?
Question 3 options:
3/5
2/5
1/2
2/3
1 answer:
The answer is the second option 2/5 there are 25 all together divide to make it 5 then there are 2/5 of that five that are girls
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D) 12 would NOT be a possible length for the third side because the sum of the 2 shorter legs should be greater than the longest leg.
Answer:
16
Step-by-step explanation:
Answer:
Part A
16y = 7x + 101
Part B
3y = 5x + 30
Part C
y = -5x/3
Part D
x = -3
What do you mean suhdbebejsjdudbdndndhdnnd
Answer: B = 9
Step-by-step explanation:
16-b=7
Rearrange so we can subtract 16 by 7
16 - 7 = 9
Substituting 9 for b and making sure it's correct.
16 - 9 = 7
