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Oduvanchick [21]
3 years ago
15

Examine the following genetic sequences and determine which pair are the most similar based on their ED (evolutionary distances)

.Species 1 = ATTGGCCATTSpecies 2 = ATTCCGGTTTSpecies 3 = TTTGGCCATTSpecies 4 = ATTCCCCCCC
Biology
1 answer:
kakasveta [241]3 years ago
8 0

Answer:

Species 1 = ATTGGCCATT and Species 3 = TTTGGCCATT are the most similar.

Explanation:

Evolutionary distance (ED) is defined as the total number of substitutions of nucleotide in one site between two DNA sequences that are homologous. It is also referred to as the number of substitutions of amino acid in one site between two protein sequences that are homologous. Based on the definition of ED, the two most similar species are species 1 and 3.

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Answer:

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To calculate this we will use the light equation:
c=λ*f

We have Frequency f=9.4* 10^{9}Hz.
We know that speed of light in vacuum is c =3.8* 10^{8} m/s.
Since a unit of speed of light is m/s, we can change the unit of frequency Hz to 1/s, since Hz means cycles per second (f=1/T).

So:
f=9.4* 10^{9}1/s
<span>c =3.8* 10^{8} m/s
</span>
<span>c=λ*f
</span>⇒ λ= \frac{c}{f}
⇒ λ= \frac{3.8* 10^{8}}{9.4* 10^{9}}
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Answer:

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