4 tables = 1 group. So in 10 groups of tables, there are 40 tables. Each table seats 8 students, so you multiply 8 by 40, and that leaves your answer as 320 students. :)
To find:
An irrational number that is greater than 10.
Solution:
Irritation number: It cannot be expression in the form of
, where,
are integers.
For example:
.
We know that square of 10 is 100. So, square root of any prime number is an example of an irrational number that is greater than 10.
First prime number after 100 is 101.
Required irrational number 
Therefore,
is an irrational number that is greater than 10.
Answer:
Joe Mama :))))))))))))))))))))))
Step-by-step explanation:
Answer:
-sqrt(3) -i = 2 cis (7pi/6)
Step-by-step explanation:
-sqrt(3) -i
We can find the radius
r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)
= sqrt( 3 + 1)
= sqrt(4)
= 2
theta = arctan (y/x)
arctan (-1/-sqrt(3))
arctan (1/sqrt(3))
theta = pi/6
But this is in the first quadrant, and we need it in the third quadrant
Add pi to move it to the third quadrant
theta = pi/6 + 6pi/6
=7pi/6
-sqrt(3) -i = 2 cis (7pi/6)
-3a+3a+6=7
0a=1
a=error. As a result, this equation has 0 solution. Hope it help!