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tino4ka555 [31]
2 years ago
13

I’m thinking of a ten-digit integer whose digits are all distinct. It happens that the number formed by the first n of them is d

ivisible by n for each n from 1 to 10. What is my number?
Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0
The problem here takes a brilliant mind to answer this. This problem can easily be answered using programming because we can not then and there push all the possibilities using paper and pen.
The answer is 3816547290. 
Trying all the possibilities starting form 1000000080 (we are sure that the last number should be 0). Then traversing that number until 9999999990. Each traverse, check the number if its divisible to n, so on and so forth.
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In the cafeteria tables are arranged in groups of 4, with each table seating 8 students. How many students can sit at 10 groups
Arisa [49]
4 tables = 1 group. So in 10 groups of tables, there are 40 tables. Each table seats 8 students, so you multiply 8 by 40, and that leaves your answer as 320 students. :)
4 0
2 years ago
Give me an example of an irrational number that is greater than 10
Pavel [41]

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of \dfrac{p}{q}, where, q\neq 0, p,q are integers.

For example: \sqrt{2}\sqrt{3},\pi, 1.263689...,etc..

We know that square of 10 is 100. So, square root of any prime number is  an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number =\sqrt{101}

Therefore, \sqrt{101} is an irrational number that is greater than 10.

5 0
3 years ago
Three interior angles of a polygon are,100degrees,120degrees,and 108degrees.Find the remaining two sides,if one of them is three
k0ka [10]

Answer:

Joe Mama :))))))))))))))))))))))

Step-by-step explanation:

8 0
3 years ago
Convert -√3-i to polar form.
Jlenok [28]

Answer:

-sqrt(3) -i = 2 cis (7pi/6)

Step-by-step explanation:

-sqrt(3) -i

We can find the radius

r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)

  = sqrt( 3 + 1)

  = sqrt(4)

  = 2

theta = arctan (y/x)

          arctan (-1/-sqrt(3))

         arctan (1/sqrt(3))

theta = pi/6

But this is in the first quadrant, and we need it in the third quadrant

Add pi to move it to the third quadrant

theta = pi/6 + 6pi/6

         =7pi/6


-sqrt(3) -i = 2 cis (7pi/6)

6 0
3 years ago
Read 2 more answers
How many solutions does the equation −3a + 3a + 6 = 7 have?
Irina18 [472]
-3a+3a+6=7
0a=1
a=error. As a result, this equation has 0 solution. Hope it help!
8 0
3 years ago
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