Given three side lengths, for example, a, b and c, you can form the triangle when
![a+b>c,\\ a+c>b,\\ b+c>a.](https://tex.z-dn.net/?f=%20a%2Bb%3Ec%2C%5C%5C%20a%2Bc%3Eb%2C%5C%5C%20b%2Bc%3Ea.%20)
If this property holds, then one triangle you can form. Each next triangle with the same sides lengths will be congruent to the first triangle by SSS postulate.
SSS postulate says: If the three sides of a triangle are congruent to the three sides of another triangle, then the two triangles are congruent.
Answer: 1 triangle, correct option is A.
Answer:
80°
Step-by-step explanation:
The sum of the measures of the acute angles in a right triangle is 90°. The sum of ratio measures in the ratio 8 : 1 is (8+1) = 9. Thus, each of those measures stands for 90°/9 = 10°. Then the angle ratio is ...
80° : 10° = 8 : 1
The measure of the largest acute angle in the triangle is ...
10° × 8 = 80°
D would be the answer my sir
Answer:
ttt
htt
tht
tth
hht
thh
hth
hhh
these are the possible outcomes of the three outcomes
so probability of hhh = 1/8
![a(1)=10 a(2)=20 a(3)=40](https://tex.z-dn.net/?f=a%281%29%3D10%20a%282%29%3D20%20a%283%29%3D40)
Lets look at available choices:
1) ![a(n)=10(2)^n](https://tex.z-dn.net/?f=a%28n%29%3D10%282%29%5En)
![a(1)=10*2=20](https://tex.z-dn.net/?f=a%281%29%3D10%2A2%3D20)
wrong as a(1) should be 10
2) ![a(n)=10*2^{n-1}](https://tex.z-dn.net/?f=a%28n%29%3D10%2A2%5E%7Bn-1%7D)
is the right choice because if you put 1 as n in the first case you will get:
3) ![a(n)=10+2n](https://tex.z-dn.net/?f=a%28n%29%3D10%2B2n)
![a(1)=10+2=12](https://tex.z-dn.net/?f=a%281%29%3D10%2B2%3D12)
wrong as a(1) should be 10
4) ![a(n)=10+2(n-1)](https://tex.z-dn.net/?f=a%28n%29%3D10%2B2%28n-1%29)
![a(1)=10](https://tex.z-dn.net/?f=a%281%29%3D10)
right but...
![a(2)=10+2=12](https://tex.z-dn.net/?f=a%282%29%3D10%2B2%3D12)
wrong as a(2) should be 20
3) and 4) can be dismissed, at once, because the is addition sign between them, and consecutive numbers should be multiplied.
In short 2) is the right answer