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3 years ago

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A walkway is being constructed using square cement tiles that each have an area of 19.0 ft2. 6 tiles will be lined up end to end

to construct the walkway. What is the total length of the walkway? Round your answer to the nearest tenth of a foot. Your Answer:

1 answer:

allochka39001 [22]3 years ago

7 0

Answer:

26.3 feet

Step-by-step explanation:

We have to first find the length of the side of each tile.

The area of each tile is 19.2 $ft^2$ .

The area of a square is:

A = $L^2$

where L = length of side

Therefore:

$19.2 = L^2\\\\L = \sqrt{19.2} = 4.38 feet$

6 tiles will be lined end to end to construct the walkway, hence, the length of the walkway is:

6 * 4.38 ≅ 26.3 feet

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A book claims that more hockey players are born in January through March than in October through December. The following data sh

denis-greek [22]

Complete question :

Birth Month Frequency

January-March 67

April-June 56

July-September 30

October-December 37

Answer:

Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.

Step-by-step explanation:

Observed value, O

Mean value, E

The test statistic :

χ² = (O - E)² / E

E = Σx / n = (67+56+30+37)/4 = 47.5

χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295

Degree of freedom = (Number of categories - 1) = 4 - 1 = 3

Using the Pvalue from Chisquare calculator :

χ² (18.295 ; df = 3) = 0.00038

Since the obtained Pvalue is so small ;

P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.

5 0

2 years ago

Help answer both plz!

Sphinxa [80]

Answer:

3.6666 (I didn't round)

Repeating decimal

Step-by-step explanation:

We know that

2/3

is the same as

2÷3

Therefore:

3 2/3 = 3+(2÷3) = 3 + 0.6666 =3.6666

A repeating decimal is one that keeps going and repeats a pattern. This is decimal keeps going and repeats a pattern so it is a repeating decimal.

A terminating decimal is one that terminates or ends. This decimal does not terminate or end. It keeps going.

Hope this helped.

6 0

2 years ago

Listed below are amounts (in millions of dollars) collected from parking meters by a security service company and other compan

Vikentia [17]

Answer:

$CV=\frac{0.1252}{1.57}=0.07975$

$CV=\frac{0.1317}{1.72}=0.07657$

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

Step-by-step explanation:

The coefficient of variation of a sample is defined as the ratio between the mean standard deviation and the sample mean. And it represents the percentage relation of the variation of the data with respect to the average.

$CV=\frac{S}{\bar X}$

In the case of the first sample you have:

$CV=\frac{0.1252}{1.57}=0.07975$

In the case of the second sample you have:

$CV=\frac{0.1317}{1.72}=0.07657$

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

6 0

3 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

Can someone please help fast will give brainelist

Vanyuwa [196]

Answer:

A.

Step-by-step explanation:

y = mx + c

m = y - y¹ / x - x¹

= 4-3 / 4-2

= 1/2

using (4,4)

4 = 1/2 × 4 + c

4 = 2 + c

c = 2

equ..=

y = 1/2x + c

7 0

3 years ago