The matrix R represents the reflection matrix for the provided vertices, and graph A represents the pre-image and the image on the same coordinate grid.
<h3>What is the matrix?</h3>
It is defined as the group of numerical data, functions, and complex numbers in a specific way such that the representation array looks like a square, rectangle shape.
We have vertices shown in the picture.
Form a matrix using the vertices:
![= \left[\begin{array}{ccc}-3&5&6\\7&3&-5\\\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%266%5C%5C7%263%26-5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To reflect over the x-axis, multiply by the reflection matrix:
![= \left[\begin{array}{ccc}1&0\\0&-1\\\end{array}\right]\left[\begin{array}{ccc}-3&5&6\\7&3&-5\\\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%266%5C%5C7%263%26-5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\rm R= \left[\begin{array}{ccc}-3&5&6\\-7&-3&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Crm%20R%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%266%5C%5C-7%26-3%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The above matrix represent the reflection matrix.
Thus, the matrices R represents the reflection matrix for the provided vertices, and graph A represents the pre-image and the image on the same coordinate grid.
Learn more about the matrix here:
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Answer:
mean is 4
Step-by-step explanation:
Answer:
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Step-by-step explanation:
A
D
C
B
I believe those are your answers
Since players are losing points every time they land on a red space, it is -50,
Here's our equation where c equals the amount of times.
-50C=-450
We need C by itself, we need to divide.
-450÷-50=9
Since there is no other way to lose points, we don't have to worry about the slope in this equation. But, there might be a way to gain points. We have it set at 0 assuming that Jamie did not score any points. This allows us to get the minimum times her could have landed.
The minimum number of times he could have landed on a red space is 9 times.
