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3 years ago

What is the area of the figure?

Mathematics

1 answer:

Paladinen [302]3 years ago

3 0

What you would need to do, is add the area of all the rectangles. The formula is wl or width * length. So find the are of all 3 rectangles, starting from the top:

5*2 = 10

3*2 = 6

5(because the rectangles are the same length)*2=10

10+10+6=26. The area of your rectangle is 26 units

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The phone lines to an airline reservation system are occupied 40% of the time. Assume that the events that the lines are occupie

nikitadnepr [17]

Answer:

a) $P(X=3)$

And we can use the probability mass function and we got:

$P(X=3) = (10C3) (0.4)^3 (1-0.4)^{10-3} = 0.215$

b) For this case we want this probability:

$P(X \geq 1)$

and the probability that the one call would be not occupied is 1-0.4=0.6

And if we use the complement rule we got:

$P(X \geq 1)= 1-P(X$

$P(X=0) = (10C0) (0.6)^0 (1-0.6)^{10-0} = 0.000105$

$P(X \geq 1)= 1-P(X$

c) $E(X) = np = 10*0.4 = 4$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

a. What is the probability that for exactly three calls, the lines are occupied?

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.4)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And for this case we want this probability:

$P(X=3)$

And we can use the probability mass function and we got:

$P(X=3) = (10C3) (0.4)^3 (1-0.4)^{10-3} = 0.215$

b. What is the probability that for at least one call, the lines are not occupied?

For this case we want this probability:

$P(X \geq 1)$

and the probability that the one call would be not occupied is 1-0.4=0.6

And if we use the complement rule we got:

$P(X \geq 1)= 1-P(X$

$P(X=0) = (10C0) (0.6)^0 (1-0.6)^{10-0} = 0.000105$

$P(X \geq 1)= 1-P(X$

c. What is the expected number of calls in which the lines are all occupied?

For this case the expected value is given by:

$E(X) = np = 10*0.4 = 4$

8 0

3 years ago

What is the image of the point (4,5) after a rotation of 90° counterclockwise about<br> the origin?

inn [45]

Answer:

A counterclockwise rotation of 270º about the origin is equivalent to a clockwise rotation of 90º about the origin. Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.

Hope it helped u if yes mark me BRAINLIEST... Plz. Plz plz!

Tysm!

7 0

4 years ago

87/100 in simplest form

Paladinen [302]

The fraction Is already in its simplest form :)

They do not have any common factors

6 0

3 years ago

Compare the two box plots. Which of the following statements is not true. Whoever gets right gets Brainly

Tom [10]