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castortr0y [4]
3 years ago
7

Please help!!

Mathematics
1 answer:
garik1379 [7]3 years ago
5 0

Given:

The radius of the cone = 14 ft

The slant height of the cone = 27 ft

To find the lateral surface area and the total surface area of the given cone.

Formula

The lateral surface area of the cone is

LSA = \pi rl and

The total surface area of the cone is

TSA = \pi r^{2} + \pi r l

where,

r be the radius and

l be the slant height of the cone.

Now

Taking r = 14 and l = 27 we get

LSA = \pi (14)(27) sq ft

or, LSA = 1187.5 sq ft

Again,

TSA = \pi(14^2)+\pi (14)(27) sq ft

or,TSA = 1803.3 sq ft

Hence,

The lateral surface area of the cone is 1187.5 sq ft and the total surface area of the cone is 1803.3 sq ft. Option C.

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The correct answer are A. and B.

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4 years ago
20% of what number is 18<br> Explain.
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In this question, the thing that needs to be found is the number whose 20% would be 18. The information's required for getting to the solution are already provided in the question. based on those given information's, the answer can be deduced very easily.
Let us assume the unknown number to be = x
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8 0
3 years ago
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Problem PageQuestion The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate paramet
asambeis [7]

Answer:

<em>t = 1.51</em>

Step-by-step explanation:

<u>Exponential Model</u>

The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.

The model can be expressed as

M=M_oe^{kt}

In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.

The value of k is not precisely given in the question, we are assuming k=-0.2

The model is now

M=M_oe^{-0.2t}

We are required to compute the time it takes the mass to reach one-half of its initial value:

\displaystyle \frac{M_o}{2}=M_oe^{-0.2t}

Simplifying

\displaystyle \frac{1}{2}=e^{-0.2t}

Taking logarithms

\displaystyle ln\frac{1}{2}=ln(e^{-0.2t})=-0.2t

Solving for t

\displaystyle t=-\frac{ln\frac{1}{2}}{0.2}=1.51

6 0
3 years ago
Laura is baking a cake. The recipe says that she has to mix 64 grams of chocolate powder to the flour. Laura knows that 1 cup of
pickupchik [31]
The answer is <span>She went over by one over six of a cup
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<span>1 cup of that particular chocolate powder has a mass of 128 grams: 1c = 128g

</span><span>64 grams of chocolate powder is x cups.
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x = 64g

1c : 128 g = x : 64g
x = </span>1c : 128 g * 64 g
x = 0.5 c
64 grams of chocolate powder is 0.5 cups = 1/2 cups

<span>She added two over three of a cup of chocolate powder: 2/3 cups

She need to add 1/2 cups: 1/2 = 3/6 cups
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So she added 4/6 - 3/6 = 1/6 cups more.
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5 0
3 years ago
1. Jemima wants to make chocolate chip walnut brownles. Chocolate chips come in a 12oz bag that costs $3. Walnuts
fomenos

Answer:

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Step-by-step explanation:

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1 bag × $2 = $2

$12 + $2 = $14 < $15

Both requirements have been met.

7 0
3 years ago
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