If there are multiple operations at the same level on the order of operations off from left to right and you work like this first noticed that there are no parentheses or exponents so we moved to multiplication and division with any sense of parentheses
x2 - 12x - 12 = 0
(x - 6)2 - 48 = 0
(x - 6)2 = 48
Hence, the answer is (B).
H(x)=5x+15+4x+20
if x=4, together it would be 5(4)+15+4(4)+20
h(x)=20+15+16+20=71
Divided by 2, they'd each get 35.5
If Frank worked alone, he'd get 5(4)+15= 35
He'd make more working together.
The least common multiple of each pair of the polynomial (5y² - 80) and
(y + 4) is equal to 5(y-4)(y+4).
As given in the question,
Given pair of the polynomial is (5y² - 80) and (y + 4)
Simplify the given polynomial using (a² -b²) = (a-b)(a +b)
(5y² - 80) = 5(y² -16)
⇒(5y² - 80) = 5(y² - 4²)
⇒(5y² - 80) = 5(y -4)(y + 4)
And (y + 4) = (1) (y+4)
Least common multiple = 5(y-4)(y+ 4)
Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).
Learn more about least common multiple here
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Answer:The first method, by substituting 5 into the expression (-2)x + 6 gives the coreect answer of -4
Step-by-step explanation:
Ist method
Substituting x = 5 into the expression (-2)x + 6, we have
(-2) 5 + 6,
=-10 + 6
=-4
2nd method
Substitute x = -1 into the expression (-2)x + 6,we have
(-2)(-1) + 6
2 +6=10
The first method, by substituting 5 into the expression (-2)x + 6 gives the coreect answer of -4
