<span>( 9 + 5i)( 9 + 8i)
= 9(9+8i)+5i(9+8i)
= 81+72i+45i+40i^2
= 81+117i+40(-1)
= 81-40+117i
= 41+117i. Answer</span>
Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
![\tan\theta=\frac{Perpendicular}{base}](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%5Cfrac%7BPerpendicular%7D%7Bbase%7D)
Here,
,Perpendicular AB = 4000
![\tan\theta=\frac{AB}{BC}](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%5Cfrac%7BAB%7D%7BBC%7D)
![\tan 11.1^{\circ} =\frac{4000}{BC}](https://tex.z-dn.net/?f=%5Ctan%2011.1%5E%7B%5Ccirc%7D%20%3D%5Cfrac%7B4000%7D%7BBC%7D)
Solving for BC, we get,
![BC=\frac{4000}{\tan 11.1^{\circ} }](https://tex.z-dn.net/?f=BC%3D%5Cfrac%7B4000%7D%7B%5Ctan%2011.1%5E%7B%5Ccirc%7D%20%7D)
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
The answer I got was y=-12x+43.
Hope this helps!
Answer:
(4,2) and (2,-2)
Step-by-step explanation:
using m=y2-y1/x2-x1
m= -2-2/2-4=-4/-2
therefore,
m=2
Answer:
2
Step-by-step explanation: