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3 years ago

Can someone help me... I’m lost :/

Mathematics

1 answer:

elixir [45]3 years ago

3 0

The true statement is - The matrix is square.

Option: C.

<u>Step-by-step explanation:</u>

The given matrix is represented as the flight times between cities in hours.

The rows are cities of departure and the columns are city of arrival.

But any of the given statements doesn't relatable to the given matrix, except the given matrix is a square.

Any matrix can be considered as square when it has equal number of rows and columns.

i.e. A m by n matrix has m=n.

where m is the number of rows and n is the number of columns.

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loris [4]

The awnsers is D (.

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3 years ago

Decrease 845g by 62%

Phoenix [80]

845* (100-62)%
=845*38%
=845*38/100
=32110/100=321,1

4 0

3 years ago

Read 2 more answers

An outdoor ice skating arena is in the shape of a circle with a diameter of 42 feet. Which of the following is closest to the ar

ioda

Answer:

Step-by-step explanation:

Since the outdoor ice skating arena is in the shape of a circle, we would determine its area by applying the formula for determining the area of a circle which is expressed as

Area = πr²

Where

π is a constant whose value is 3.14

r represents the radius of the circle

From the information given,

Diameter = 42 feet

Radius = diameter/2 = 42/2 = 21 feet

Therefore,

Area = 3.14 × 21² = 1384.74 square feet

Rounding up to the nearest whole number, area of the outdoor ice skating arena would be 1385 square feet

3 0

3 years ago

Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

4 0

3 years ago

For what value of X-1/3x=12

vovangra [49]

Answer:

Step-by-step explanation:

7 0

4 years ago