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Define the two numbers
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Let the first number be x.
Let the second number be y.
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Form equations and solve x and y
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x + 2y = 14 ------------------ (1)
2x + y = 31 ------------------ (2)
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Equation (1) x 2
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2x + 4y = 28 ---------------(1a)
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Equation (1a) - 2
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3y = 28 - 31
3y = -3
y = -1
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Substitute y = -1 into (1)
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x + 2(-1) = 14
x -2 = 14
x = 14 + 2
x = 16
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Answer: x =16, y = -1
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Answer: 69
Step-by-step explanation:
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
2.
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
X = locker number
x + x+1 = 131
2x + 1 = 131
2x = 130
x = 65
The locker numbers are 65 and 66
C is 0.003 and so is a and so is b