Finding angle measures given two parallel lines cut by a transversal

Mathematics

1 answer:

Elan Coil [88]3 years ago

8 0

M∠8 = 147°

m∠3 + m∠8 = 180° (because they are supplementary angles)
m∠3 + 147 = 180
m∠3 + 147 (-147) = 180 (-147)
m∠3 = 180 - 147
m∠3 = 33°

m∠2 + m∠3 = 180° (again they are supplementary)
plug in 33 for m∠3
m∠2 + 33 = 180
m∠2 + 33 (-33) = 180 (-33)
m∠2 = 180 - 33
m∠2 = 147°

hope this helps

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