Answer:
Step-by-step explanation:
Let the number by x
Sum of x and 8: x +8
(x + 8)³
The value of x and y in the given equation is determined -1 and -2 respectively.
<h3>
Value of x and y</h3>
The value of x and y can be determined by solving the two equations simultaneously.
y = -2x - 4 ----- (1)
y = 4x + 2 ----- (2)
solve (1) and (2) together
-2x - 4 = 4x + 2
-6x = 6
x = -1
y = 4(-1) + 2
y = -4 + 2
y = -2
Learn more about equations here: brainly.com/question/2972832
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Answer:
Step-by-step explanation:
Slope intercept form: 
when 
is the slope of the line and 
is the y-intercept (the y-coordinate of the point the line crosses the y-axis)
<u>1) Find the slope (</u><u>)</u>
when the points are 
and 
We can use any two points that the table gives us to plug into this equation. For example, we can use the points (14,0) and (0,7):
Simplify the fraction
So far, our equation looks like this:
<u>2) Find the y-intercept (</u><u>)</u>
The y-intercept is the y-coordinate of the point the line crosses the y-axis, or in other words, it's the value of y when x is equal to 0.
Looking at the table, we can see that y is equal to 7 when x is equal to 0, so, therefore, 
.
Now, this is our final equation after plugging in and :
I hope this helps!
This is a simple subtraction problem, but since you are in Elementary School, I will help you out.
Subtract $4,190.67 by $3,655.11 (remember, the bigger number should come first)
4,190.67
<span>-3,655.11
</span> ...56
When a small number is on top of a bigger number, borrow 1 number from the number next to it (in this case, 0 is smaller than 5, so you must borrow 1 number from 9, making it to 8), then add the small number by 10 (0+0=10)
<span>Then we continue...
</span> 4,190.67
<span>-3,655.11
</span> 35.56
Do the same thing with 4 and 1.
4,190.67
<u>-3,655.11</u>
535.56
<em><u>Answer: $535.56</u></em>
Answer:
{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}
Step-by-step explanation:
sinx can run from -1 to +1
2sinx can run from -2 to +2
2sinx -1 can run from -3 to +1
However, the square root is imaginary when x < 0. So, the condition is
2sinx -1 ≥ 0
2sinx ≥ 1
sinx ≥ ½
x ≥ π/6 (30°)
So, in the interval [0, 2π], π/6 ≤ x ≤ 5π/6
However, the sine is a cyclic function and repeats itself every 2π.
Over all real numbers, the condition is (π/6 +2πn) ≤ x ≤ (5π/6 + 2πn).
The domain is then
{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}
