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Sergio039 [100]
4 years ago
13

How many numbers round to 600

Mathematics
1 answer:
AysviL [449]4 years ago
3 0
I believe it would be 9.
595,596,597,598,599.
601,602,603,601
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a fruit company delivers its fruit in two typed of boxes: large and small. A delivery of 2 large boxes and 3 small boxes has a t
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A fruit company delivers its fruit in two types of boxes: large and small. A delivery of
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7 0
3 years ago
Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.
Amiraneli [1.4K]

The correct representations of the given inequality are

–6x + 15 < 10 – 5x

and

A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options

<h3>Solving inequality</h3>

From the question, we are to solve the inequality

The given inequality is

–3(2x – 5) < 5(2 – x)

First, clear the brackets

–6x + 15 < 10 – 5x

NOTE: This is one of the correct representations of the inequality

Collect like terms

-6x + 5x < 10 - 15

-x < -5

Divide both sides by -1 and flip the sign

x > 5

Representing this on a number line, we get a number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is pointing to the right.

Hence, the correct representations of the given inequality are

–6x + 15 < 10 – 5x

and

A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options

Learn more on Inequalities here: brainly.com/question/246993

#SPJ1

6 0
2 years ago
Find the diagonal of the rectangular prism to the nearest tenth.<br> 4 in<br> 3 in<br> 10 in
hoa [83]

Given:

Consider the dimensions of a rectangular prism are 4 in by 3 in by 10 in.

To find:

The length of the diagonal.

Solution:

Length of diagonal of a rectangular prism is:

d=\sqrt{l^2+b^2+h^2}

Where l is length, b is breadth and h is height.

The dimensions of a rectangular prism are 4 in by 3 in by 10 in. So, the length of diagonal of the rectangular prism is:

d=\sqrt{(4)^2+(3)^2+(10)^2}

d=\sqrt{16+9+100}

d=\sqrt{125}

d=5\sqrt{5}

Approximate the value to the nearest tenth.

d\approx 11.2

Therefore, the length of diagonal of the rectangular prism is 11.2 in.

5 0
3 years ago
What is the y-intercept for the graph of this line?<br> 3x - 5y= 6
Korvikt [17]

Answer:

y-intercept: (0, -1.2)

Step-by-step explanation:

3 0
3 years ago
Integrate the following
enot [183]

I suppose you mean to have the entire numerator under the square root?

\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx

We can use a trigonometric substitution to start:

x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt

Then for x=2, t=\sec^{-1}1=0; for x=4, t=\sec^{-1}2=\frac\pi3. So the integral is equivalent to

\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt

We can write

\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t

so the integral becomes

\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}

7 0
3 years ago
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