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Leokris [45]
4 years ago
11

What is the distance between (-5, -6)(−5,−6)and (-3, -8)(−3,−8)?

Mathematics
1 answer:
sertanlavr [38]4 years ago
8 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{-8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-3-(-5)]^2+[-8-(-6)]^2}\implies d = \sqrt{(-3+5)^2+(-8+6)^2} \\\\\\ d = \sqrt{2^2+(-2)^2}\implies d = \sqrt{4+4}\implies d = \sqrt{8}\implies d\approx 2.83

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The width of a rectangle is only 15% of its length. If the perimeter of the rectangle is 46, what is the length
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Answer:

20 units

Step-by-step explanation:

Let the length be x. According to the question,

  • Length = x
  • Width = 15% of the length

➝ Width = 15% of the length

➝ Width = 15/100x

➝ Width = 3/20x

We have the perimeter of the rectangle that is 46 units.

\longrightarrow \sf {Perimeter_{(Rec.)} = 2(L + W) } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{20x + 3x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{23x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {\dfrac{46}{2}=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23 \times 20 = 23x} \\

\longrightarrow \sf {460= 23x} \\

\longrightarrow \sf {\cancel{\dfrac{460}{23}} = x} \\

\longrightarrow \underline{\boxed{ \bf {20\; units = x}}} \\

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