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velikii [3]
4 years ago
14

Find the inverse function of m(x) = 5x - 5 A m-1(x) = 5x + 5 B m-1(x) = -5x + 5 C m-1(x) = x+5/5 D m-1(x) = x+5/-5x

Mathematics
2 answers:
Kamila [148]4 years ago
8 0
Switch your X and Y =

x = 5y - 5

Add 5 to both sides

x +5 = 5y

Divide both sides by 5

M -1 (x) = x+5/5

bogdanovich [222]4 years ago
6 0
Hi there!

m(x) = 5x - 5
First replace m(x) by y.

y = 5x - 5
To find the inverse function we must switch the places from the variables x and y.

x = 5y - 5
Now we need to isolate the y again to find the formula of the inverse function. First add 5 to both sides.

x + 5 = 5y
Switch sides.

5y = x + 5
And finally divide both sides by 5.

y =  \frac{x + 5}{5}
And therefore we can conclude the following:

m {}^{ - 1} (x) =  \frac{x + 5}{5}
The answer is C.
~ Hope this helps you!







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Stels [109]

let's recall that an inverse function has the same pair of coordinates as the original function, but backwards, or namely the inverse's range is the original's domain.

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3 years ago
What is the inverse of this function? (Function in photo)
valkas [14]

Given:

The function is

f(x)=-\dfrac{1}{2}\sqrt{x+3},x\geq -3

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The inverse of the given function.

Solution:

We have,

f(x)=-\dfrac{1}{2}\sqrt{x+3}

Put f(x)=y.

y=-\dfrac{1}{2}\sqrt{x+3}

Interchange x and y.

x=-\dfrac{1}{2}\sqrt{y+3}

Isolate the variable y.

-2x=\sqrt{y+3}

(-2x)^2=y+3

4x^2-3=y

y=4x^2-3

Putting y=f^{-1}(x), we get

f^{-1}(x)=4x^2-3

For x\geq -3,

x+3\geq 0

\sqrt{x+3}\geq 0

-\dfrac{1}{2}\sqrt{x+3}\leq 0

f(x)\leq 0

It means for function f(x)\leq 0 and for inverse function x\leq 0 because the range of the function is the domain of inverse function.

Therefore, f^{-1}(x)=4x^2-3 for x\leq 0.

3 0
3 years ago
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Cloud [144]
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Step-by-step explanation:

<u><em>The complete question is</em></u>

Given (1+cosx)/(sinx) + (sinx)/(1+cosx) =4, find a numerical value of one trigonometric function of x.

a. tanx=2

b. sinx=2

c. tanx=1/2

d. sinx=1/2

we have

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Find the common denominator and adds the fractions

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Expanded the numerator

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Remember that

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substitute

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Factor 2 in the numerator

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Simplify

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