Answer:
She did not use the reciprocal of the divisor.
She added the numerators.
The answer is 5 hope that helps
Answer:
Problem 9: -1/2
Problem 10: 1/5
Step-by-step explanation:
Problem 10: Label the given ln e^(1/5) as y = ln e^(1/5).
Write the identity e = e. Raise the first e to the power y and the second e to the power 1/5 (note that ln e^(1/5) = 1/5). Thus, we have:
e^y = e^(1/5), so that y = 1/5 (answer).
Problem 9: Let y = (log to the base 4 of) ∛1 / ∛8, or
y = (log to the base 4 of) ∛1 / ∛8, or
y = (log to the base 4 of) 1 /2
Write out the obvious:
4 = 4
Raise the first 4 to the power y and raise the second 4 to the power (log to the base 4 of) 1 /2. This results in:
4^y = 1/2. Solve this for y.
Note that 4^(1/2) = 2, so that 4^(-1/2) = 1/2
Thus, y = -1/2
