I don't remember the names of the theorems at all, but we know that AD ≈ DE ≈ EB (Segment Addition). Which means <ACD ≈ <DCE ≈ <ECB (not completely sure how to prove this). Therefore, <1 ≈ <2. (Don't forget to state that <1 ≈ <ACD and <2 ≈ <ECB). With this and Angle Addition, we know that <ACE ≈ <DCB, so with SAS Congruence Theorem, we can prove ΔACE ≈ ΔBCD.
Hope that helps
Answer: 1500
Step-by-step explanation:
5 m/s in 0 m/s in 1 sec
so its 1500
Answer:
Choice D
y = 3(2/3)^x
Step-by-step explanation:
a) y = 2(3/2)^x = 3^x (pretty close)
b) y = (2/3)^x (wrong, coming from the wrong side)
c) y = 2(3)^x = 6^x (too close to y line)
d) y = 3(2/3)^x = 2^x (looks right)
Maria had 13 points and jane had 8 points
Answer:
12.922848
Step-by-step explanation:
I used my calculator
